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Calculate the value of `DeltaG` at `700K` for the reaction, `nX to mB`. Given that value of `DeltaH=-113kJ mol^(-1)` and `DeltaS=-145JK^(-1)mol^(-1).` |
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Answer» `DeltaG=DeltaH-TDeltaS` `=-113xx10^(3)-700xx(-145) J mol^(-1)` `DeltaG=-113000+101500` `=-11500 J mol^(-1)` `DeltaG=-11.50 k J mol^(-1)` |
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