1.

Calculate the value of `DeltaG` at `700K` for the reaction, `nX to mB`. Given that value of `DeltaH=-113kJ mol^(-1)` and `DeltaS=-145JK^(-1)mol^(-1).`

Answer» `DeltaG=DeltaH-TDeltaS`
`=-113xx10^(3)-700xx(-145) J mol^(-1)`
`DeltaG=-113000+101500`
`=-11500 J mol^(-1)`
`DeltaG=-11.50 k J mol^(-1)`


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