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Calculate the value of the acceleration due toat a place 3,200 km above the surface of the earth.9.gravity |
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Answer» Assume- h= 3200km = 3200000m = 3.2 x10^6 R= 6400km = 6400000m = 6.4 x 10^6 g= 9.8m/s^2We know that- g'= g[R^2/(R+h)^2] = 9.8(40.96 x 10^12/92.16 x 10^12) = 9.8 x 4/9 = 4.355m/s^2 ~ 4.4m/s^2 Thus, value of g at a place 3200km above surface of the earth is 4.4m/s^2. v good |
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