1.

calculate the voltage needed to balance on oil drop carrying 10e when located b/w the plates of a capacitor which are 5mm apart . the mass of oil drop​

Answer»

The gravitational force on the oil drop = MG = 3 x 10-16 x 10 = 3 x 10-15 N.

Magnitude of the electrostatic force NEEDED balance this force is given by

E = mg/10e = (3 x 10-15) / (10 x 1.6 x 10-19) = 0.1875 x 104 V/m.

Voltage ACROSS the places of the capacitor is then given by

V = Ed = 0.1875 x 104 x 5 x 10-3 = 9.375 Volts.


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