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Calculate the wavelength of radiation emited when an electron in a hydrogen atom makes a transition from an energy level with `n = 3` to a level with `n= 2` |
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Answer» Correct Answer - A::B::D `E_(n) = -(1312)/(n^(2)) kJ mol^(-1)` `Delta E = E_(2) - E_(1) = -1312 ((1)/(9) - (1)/(4)) ` `= 182.2 k J mol^(-1)` `Delta E "atom"^(-1) = (182.2)/(6.023 xx 10^(23)) k J "atom"^(-1)` `= 3.03 xx 10^(-19) J "atom"^(-1)` `E = hv,v = (c )/(lambda)`, `lambda = (hc)/(E ) = ((6.63 xx 10^(-34))(3 xx 10^(8)))/(3.03 xx 10^ (-19))` `= 6.65 xx 10^(-7) = 656 nm` |
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