1.

Calculate the wavelength of radiation emited when an electron in a hydrogen atom makes a transition from an energy level with `n = 3` to a level with `n= 2`

Answer» Correct Answer - A::B::D
`E_(n) = -(1312)/(n^(2)) kJ mol^(-1)`
`Delta E = E_(2) - E_(1) = -1312 ((1)/(9) - (1)/(4)) `
`= 182.2 k J mol^(-1)`
`Delta E "atom"^(-1) = (182.2)/(6.023 xx 10^(23)) k J "atom"^(-1)`
`= 3.03 xx 10^(-19) J "atom"^(-1)`
`E = hv,v = (c )/(lambda)`,
`lambda = (hc)/(E ) = ((6.63 xx 10^(-34))(3 xx 10^(8)))/(3.03 xx 10^ (-19))`
`= 6.65 xx 10^(-7) = 656 nm`


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