1.

Calculate the work done by `0.1` mole of a gas at `27^(@)C` to double its volume at constant pressure `(R = 2 cal mol^(-1)K^(-1))`

Answer» `(V_(1))/(V_(2)) = (T_(1))/(T_(2)) rArr (V)/(2V) = (300)/(T_(2)) rArr T_(2) = 600 rArr Delta T = 300`
`W = -P Delta V = nRDelta T`
`rArr W = -0.1 xx 2 xx 300 = -60 cal`.


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