InterviewSolution
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InterviewSolution
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Calculate the work done in open vessel at `300K`, when `92g Na` reacts with water. Assume ideal gas neture. |
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Answer» `2Na +2H_(2)O rarr 2NaOH +H_(2)` Moles of `Na = (92)/(23) = 4` Mole of `H_(2)` formed `= (1)/(2) xx` Mole of `Na` used `= (1)/(2) xx 4 = 2` Work is done in giving out `2mol H_(2)`. Thus, `W =- P xx V_(H_(2)) = n_(H_(2))RT =- 2 xx 8.314 xx 300` `=- 4988.4J` The `H_(2)` liberated pushes the atmospheric gas block and thus, does work in driving back the atmosphere. Note that in the case of closed vessel, `DeltaV = 0`. Therefore, `W = 0`. |
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