1.

Calculate the work done when 1 moleof an ideal gas is compressed reversibly from 1.0 bar to 4.00 bar at constant temperature of 300KA. `3.46 kJ`B. `-8.20 kJ`C. `18.02kJ`D. `-14.01kJ`

Answer» Correct Answer - A
`w= - 2.303 nRT log. (P_(1))/(P_(2))= - 2.303 xx 1 xx 8.314 xx 300 log. (1)/(4) = 3458J = 3.458 kJ`


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