Calculate the work done when 2 moles of an ideal gas expands reversibl

1.	Calculate the work done when 2 moles of an ideal gas expands reversibly and isothermally from a volume of 500 ml to a volume of 2 L at 25°C and normal pressure.
Answer» n = 2 moles V_i = 500 ml = 0.5 lit V_f = 2 lit T = 25°C = 298 K w = -2.303 nRT log\((\frac{V}{V_i})\) w = -2.303 x 2 x 8.314 x 298 x log\(\frac{2}{0.5}\) w = -2.303 x 2 x 8.314 x 298 x log(4) w = -2.303 x 2 x 8.314 x 298 x 0.6021 w = -6871 J w =-6.871 kJ.

Calculate the work done when 2 moles of an ideal gas expands reversibly and isothermally from a volume of 500 ml to a volume of 2 L at 25°C and normal pressure.

Answer»

n = 2 moles

V_i = 500 ml = 0.5 lit

V_f = 2 lit

T = 25°C = 298 K

w = -2.303 nRT log\((\frac{V}{V_i})\)

w = -2.303 x 2 x 8.314 x 298 x log\(\frac{2}{0.5}\)

w = -2.303 x 2 x 8.314 x 298 x log(4)

w = -2.303 x 2 x 8.314 x 298 x 0.6021

w = -6871 J

w =-6.871 kJ.

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Calculate the work done when 2 moles of an ideal gas expands reversibly and isothermally from a volume of 500 ml to a volume of 2 L at 25°C and normal pressure.

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