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Calculate the work done when a system raises a colume of water of radius `5.0mm` through `10cm`. |
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Answer» Work is given: `W =- mgh` where, `m = Volume xx Density` `pir^(2)l xxd = (22)/(7) xx (0.5)^(2) xx 10 xx1` `g = 980 cm s^(-2)` `h = (10)/(2) = 5cm` [The centre of mass of colume lies half way along its length `l`, therefore the centre of mass is raised to a height `h = (1//2)l`] `:.W =- (22)/(7) xx (0.5)^(2) xx 10 xx 980 xx 5xx1` `=- 38.5 xx 10^(3) erg =- 3.85 xx 10^(-3)J` The nagative sign shows that systwm shows a decrease in internal enegry. |
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