1.

Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60 km/h?

Answer»

BY WORK ENERGY THEOREM
WORK DONE IN STOPING  = CHANGE IN KINETIC ENERGY = \frac{1}{2} m v^{2}
                                                                    
= \frac{1}{2}*1500 (60* \frac{5}{18} )^{2}

=208333.333 Joule



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