Calculate what fraction of gas molecules (a) traverses without collisions the distances exceeding the mean free path `lamda` , (b) has the free path values lying within the inerval from `lamda` to `2 lamda`.

Calculate what fraction of gas molecules (a) traverses without collisi

1.	Calculate what fraction of gas molecules (a) traverses without collisions the distances exceeding the mean free path `lamda` , (b) has the free path values lying within the inerval from `lamda` to `2 lamda`.
Answer» (a) The fraction of gas molecules which traverses distances exceeding the mean free path without collision is just the probability to traverse the distance `s = lamda` without collision. Thus `P = e^-1 = (1)/( e) = 0.37` This probability is `P = e^-1 - e^-2 = 0.23`.

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Calculate what fraction of gas molecules (a) traverses without collisions the distances exceeding the mean free path `lamda` , (b) has the free path values lying within the inerval from `lamda` to `2 lamda`.

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