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Calculatethe numberof watermoleculespresentin onedropof waterwhichweights 0.18 g. |
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Answer» Solution :The Molecular Mass of water `H_(2)O` is 18. 18 g of water molecule = 1 mole 0.18 g of water = `(1)/(18)xx0.18=0.01` mole. One mole of water CONTAINS `6.023xx10^(23)` (water MOLECULES) `therefore 0.01` mole of water contains `(6.023)/(1)xx10^(23)xx0.01=6.023xx10^(21)` molecules. |
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