InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
Caluculate the density of uranium `-235` nucleus. Given `m_(n) = m_(p) = 1.67xx10^(-27) kg`. |
|
Answer» Mass of uranium 235 = No. of nucleous `xxm_("nucleon")` `= A xx 1.67xx10^(-27)kg` Also volume of nucleus `= (4)/(3)pi r^(3)` `= (4)/(3) pi (1.3xx10^(-15)xx A^(1//3))^(3)` (where `A` is mass no.) `= 9.2xx10^(-45) xx A m^(3)` `:. "Density" = (m)/(V) = (1.67xx10^(-27)xx A)/(9.2xx10^(-45)xx A)` `= 1.8xx10^(17)kg m^(-3)` |
|