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Can someone help me write a Python program to accept a number and check if it's perfect using 'while' loop?

Answer»

Answer:

def isPerfect( N ):  

     

   # To store sum of divisors  

   sum = 1

     

   # Find all divisors and add them  

   i = 2

   while i * i <= n:  

       if n % i == 0:  

           sum = sum + i + n/i  

       i += 1

     

   # If sum of divisors is EQUAL to  

   # n, then n is a perfect NUMBER  

     

   return (True if sum == n and n!=1 else False)

input = int(input("Enter a number... "))

if isPerfect(input):

       print("It is a Perfect Number")

else:

       print("It is not a perfect number")

HOPE IT HELPS U. PLS MARK MY ANSWER AS BRAINLIEST.


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