Capacitor of capacitance 10 micro farad is fully charged by 200V suppl

1.	Capacitor of capacitance 10 micro farad is fully charged by 200V supply . The energy stored in the capacitor is
Answer» Given , Capacitance (C) = 10 µf or 10^(-5) f Potential difference (V) = 200 v We KNOW that , the energy stored in a CAPACITOR is given by $\boxed{ \tt{Energy \: (U) = \frac{1}{2} {(v)}^{2}C}}$ Thus , $\tt : \mapsto U = \frac{1}{2} \times {(200)}^{2} \times {(10)}^{ - 5}$ $\tt : \mapsto U = \frac{40000 \times {(10)}^{ - 5} }{2}$ $\tt : \mapsto U =2 \times {(10)}^{ - 1}$ $\tt: \mapsto U =0.2 \: joule$ ★ The energy stored in a capacitor is 0.2 J