InterviewSolution
Saved Bookmarks
| 1. |
Car A of mass 1000 kg moves on a horizontal straight road with speed 36kmh^(-1). If the force resisting the motion is 100 N, then find the power of the engine. Now, after covering 200 m distance, car A collides with a stationary car B of same mass and becomes stationary. As a result car B start moving on the horizontal road, then what would be the speed of car B just after the collision? (The engine of car B is off.) |
|
Answer» Frictional FORCE = 100 N POWER of engine of car A, `P=Fv` `=100xx10(because V=10ms^(-1))` `=1000W` USING the law of conservation of momentum, `m_(A)u_(A)+m_(B)u_(B)=m_(A)v_(A)+m_(B)v_(B)` `(1000xx10)+(1000xx0)=(1000xx0)+(1000xxv_(B))` `therefore v_(B)=10ms^(-1)` |
|