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Car moving with a velocity of 10 metre per second can be stopped by the application of a constant force f in a distance of 20 m if the velocity of the car is 30 metre per second it can be stopped by this force in |
| Answer» 180 metersExplaination:We'll use the EQUATION of motion:v^2 - u^2 = 2×a×sHere, v = 0 m/s as the car stops in the end.Also, since a deceleration is happening, we'll WRITE 'a' as '-a'So, the equation modifies to become as follows:- u^2 = 2×(-a)×su^2 = 2×a×ss = (u^2)/(2×a)20 = 10^2/(2×a) => 2×a = 5s = 30^2/(2×a) => s = 900/5 => [s = 180 meters] | |