1.

car travelling at 60 km/h overtakes another cartravelling at 42 km/h. Assuming each car to be 5.0 mlong, find the time taken during the overtake and thetotal road distance used for the overtake..A

Answer»

For the car with 60kmph to overtake the first car it should travel a relative distance of 10 m

(5m for catching up and 5m for getting clear ahead)

therefore Srel = 10 m

Vrel = 60-42 = 18km/hr = 5 m/s

Relative acceleration= 0 .since both are moving with constant velocities.

Now using relative motion, S = Vrel × t

therefore time ,t = S / Vrel = 10/5 =2s

Distance used to overtake is 60× 5/18× 2= 100/3 = 33.33 m



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