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car travelling at 60 km/h overtakes another cartravelling at 42 km/h. Assuming each car to be 5.0 mlong, find the time taken during the overtake and thetotal road distance used for the overtake..A |
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Answer» For the car with 60kmph to overtake the first car it should travel a relative distance of 10 m (5m for catching up and 5m for getting clear ahead) therefore Srel = 10 m Vrel = 60-42 = 18km/hr = 5 m/s Relative acceleration= 0 .since both are moving with constant velocities. Now using relative motion, S = Vrel × t therefore time ,t = S / Vrel = 10/5 =2s Distance used to overtake is 60× 5/18× 2= 100/3 = 33.33 m |
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