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car with a vertical windshield moves in a rain stoat a speed of 40 km/hr. The rain drops fall verticallwithconstant speed of 20 m/s. The angle at whichrain drops strike the windshield is -955(A) tan 9B) tan1-1(C) tan-1 32(D) tan 3 |
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Answer» the horizontal component of falling rain is 40km/hrnow convert km/hr into m/s 40*5/18=11.11m/s vertical component of falling the rain is 20 m/s Q=tan^-1(horizontal/vertical) Q=tan^-1(11.11/20) Suppose horizontal direction is represented byiunit vector. Suppose vertical direction is represented byjunit vector. Vc = Velocity of car with respect to earth is 40ikm/hr. Vr = Velocity of rain with respect to earth is 20jm/s = 72jkm/hr. Suppose the angle required is taken to be Q. tan Q = Vc / Vr = 5/9. hence, option (a) is correct. |
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