1.

Check whether – 25 is a term in the progression 5, 3, 1, ………….or not ?

Answer»

The given 5, 3, 1,…………..is an arithmetic progression here 

a = 5, d = a2 – a2 = 3 – 5 = -2 

Let -25 is some of ‘n’ th term 

i.e. an – 25 

So an = a + (n-1)d 

-25 = 5 + (n – 1)(- 2)

– 25 – 5 = (n – 1) (-2)

\(\frac{-30}{-2}\) = n – 1 

⇒  n – 1 = 15 and n = 15+ 1 = 16

So – 25 exist at 16th term in above series.



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