check whether the equation 1/2mv^2=mgh is dimensionally correct, where

1.	check whether the equation 1/2mv^2=mgh is dimensionally correct, where m is the mass of the body,v, its velocity,g is the acceleration due to gravity.
Answer» Explanation: 1/2mv^2=mgh m=M, v=LT^-1 g=LT^-2,h=L Then.... ML^2T^-2=ML^2T^-2 Hence PROVED

check whether the equation 1/2mv^2=mgh is dimensionally correct, where m is the mass of the body,v, its velocity,g is the acceleration due to gravity.

Answer»

Explanation:

1/2mv^2=mgh

m=M, v=LT^-1

g=LT^-2,h=L

Then....

ML^2T^-2=ML^2T^-2

Hence PROVED

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check whether the equation 1/2mv^2=mgh is dimensionally correct, where m is the mass of the body,v, its velocity,g is the acceleration due to gravity.​

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check whether the equation 1/2mv^2=mgh is dimensionally correct, where m is the mass of the body,v, its velocity,g is the acceleration due to gravity.