1.

Check whether the equation is dimensionally correct,v=u² + 2as?

Answer»

v= final velocity = [LT-¹]u= initial velocity=[LT-¹]a= acceleration =[LT-²]s= distance= [L]v²=u²+ 2as=>v²-u²=2as[LT-¹]²-[LT-¹]²=2[LT-²][L][L²T-²][L²T-²]=2[L²T-²]2[L²T-²]=2[L²T-²]2 is dimensionlesshence proved

tysm rukma basu



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