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Chloroform is passed from methane according to the reaction `:` `CH_(4)(g) + 3Cl_(2)(g) rarr CHCl_(3)(l) + 3HCl(g)` Calculate `Delta H ` for the reaction given that enthalpies of formation of HCl(g), `CH_(4)(g) ` and `CHCl_(3)(g)` are - 92.0 ,-74.9 and -134.3kJ per mole respectively. |
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Answer» Correct Answer - `-335.4kJ mol^(-1)` `Delta_(r) H^(@) = [ Delta_(r) H^(@)(CHCl_(3)) + 3Delta_(f)H^(@) (HCl) ]- [ Delta_(f)H^(@)(CH_(4)) + 3Delta_(f) H^(@) (Cl_(2))]` `[ ( - 134.3) + 3 (-92.0 ) ] -[( - 74.9 ) + 0]` ` = - 335.4kJ mol^(-1)` |
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