Compare the time period of 2pendulam of length 25m and 36m – InterviewSolution

1.

Compare the time period of 2pendulam of length 25m and 36m

Answer»

EXPLANATION:

TIME PERIOD of PENDULUM

$T \: = 2\pi \sqrt{ \frac{l}{g} }$

$T \: \infty \sqrt{l}$

$\frac{T1}{T2} = \frac{ \sqrt{l1} }{ \sqrt{l2} }$

$\frac{T1}{T2} = \frac{ \sqrt{25} }{ \sqrt{36} }$

$\frac{T1}{T2} = \frac{5}{6}$

T1 : T2 = 5:6

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