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Compute `Delta_(r)G` for the reaction `H_(2)O (l, 1, atm, 323 K ) to H_(2)O (g, 1 atm, 232K) ` Given that : `Delta_(vap) H at 373 K = 40.639 kJmol^(-1), C_(p)(H_(2)O, l)= 75.312 JK^(-1) mol^(-1)`, `" "C_(p)(H_(2)O, g) = 33.305 J K^(-1)mol^(-1)`. |
Answer» Correct Answer - `Delta_(r)G = 5.59 KJ mol^(-1)` `DeltaH_(373) = DeltaH _(323) - DeltaC_(p)DeltaT` `40639 = DeltaH_(323)-(33.305 - 75.312) xx 50` `DeltaH_(323) = 42739. 35 J//mol` |
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