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con14. A constant force of 12 N acts on a body for 4 s. Findthe change in the linear momentum of the body.20. AC |
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Answer» F=dp/Dr12=dp/4dp= 48 F=m(v-u)/tSo,12=m(v-u)/4Hence,m(v12=m(v-u)/4Hence,m(v-u)=12*4=48kgm/sSo, mv-mu=48kgm/sTherefore change in linear momentum of the body is 48kgm/s. 48N-s is the change in the linear momentum of the body. 48 is the correct answer of the given question |
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