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Consider a carnot cycle operating between source tempeature 750 K and sink temperature 350 K producing 1.25 J KJ of mechanical work per cycle, the heat transferred to the engine by the reserversA. 1.34 KJB. 2.34 KJC. 3.34 KJD. 4.34 KJ |
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Answer» Correct Answer - B Here `t_(1)=750 K,t_(2)=350 K`, W=1.25 Kj =1250 J Now efficiency `eta=1-(T_(2))/(T_(1))=1-(350)/(750)=(400)/(750)=(8)/(15)` As `eta=(W)/(Q_(1))` `therefore Q_(1)=(W)/(eta)=(1250)/(8//15)=(1250)/(8)xx15=2343.75 J = 2.34 KJ` |
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