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InterviewSolution
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Consider an unknow polynomial which divided by `(x - 3)` and `(x-4)` leaves remainder 2 and 1, respectively. Let R(x) be the remainder when this polynomial is divided by `(x-3)(x-4)`. If `R(x) = px^(2) + (q-1) x + 6` has no distinct real roots and `p gt 0`, then the least value of `3p + q` isA. `-2`B. `2//3`C. `-1//3`D. none of these |
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Answer» Correct Answer - 3 Let unknow polynomial be P(x). Let Q(x) and R(x) be the quatient and remainder, respectively, when it is divided by the `(x-3) (x-4)`. Then `P(x) = (x-3)(x-4) Q(x) + R(x)` Then we have `R(x) = ax + b` ` rArr P(x) = (x-3) (x-4)Q(x) + ax+ b` Given that `P(3) =2 ` and `P(4)=1` . Hence, `3a + b = 2 and 4a + b = 1` `rArr a = -1 and b= 5` `rArr R(x) = 5 -x` `- x + 5 = px^(2) + (q- 1)x + 6` `rArr px^(2) + qx + 1 = 0` Now, `p gt 0 ` and equation has no distinct real roots or equation has real and equal or imaginary roots. Then, `px^(2) + qx + 1 ge 0, AA x in R` `rArr f(3) ge rArr 9p + 3q + 1 ge 0 rArr 3p + q ge - 1//3` Hence, the least value of `3p + q` is `-1//3`. |
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