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consider `f(X) =(1)/(1+|x|)+(1)/(1+|x-1|)` Let `x_(1)` and `x_(2)` be point wher f(x) attains local minmum and global maximum respectively .If `k=f(x_(1))+f(x_(2))` then 6k-9=________. |
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Answer» Correct Answer - 8 `f(X)=(1)/(1+|x|)+(1)/(1+|x-1|)` clearly f(X) is non differeentiable at x =0,1 Also `f(1//2+x)=f(1//2-x)` Hence graph of f(x) is symmetrical about line x=`1//2` where derivation is zero Local minimum =`f(1/2)=4/3` Global maximum `=f(x)=f(1)=3/2` `terefore k=4/3+3/2=17/6` |
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