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consider P(x) to be a polynomial of degree 5 having extremum at x=-1,1 and `lim_(xrarr0) p(x)/(x^(3))-2=4` Then the value of P(x)_____. |
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Answer» Correct Answer - 2.4 Give `underset(xrarr0)lim p(x)/(x^(3))-2=4` `therefore underset(xrarr0)lim(p(x))/(x^(3))=6` consider P(x) =`ax^(5)+bx^(4)+6x^(3)` Now `P(-1)=0 rarr5a-4b=-018` and `P(1)=0 rarr 5a+4b=-18` Hence P(x) =`(-18)/(5)x^(5)+6x^(3)` or P(1)`=12/3` |
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