InterviewSolution
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InterviewSolution
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The funciton f(x)=`x^(2)+(lambda)/(x)`has aA. minimum at x =2 if `lambda` =16B. maximum at x =2 if `lambda` =16C. maximum for no real value of `lambda`D. point of inflectin at x=1 if `lambda`=-1 |
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Answer» Correct Answer - 1,3,4 `f(x)=2x-(lambda)/(x^(2)),f(x)=0` `rarr x=((lambda)/(2))^(1//3)` if `lambda=16,x=2` Now `f(x)=2+(2lambda)/(x^(3))` Thus if `lambda=16 f(x)gt0` i.e f(X) has a minimum x=2 Also `f{((lambda)/(2))^(1//3)}=2+(2lambda)/(lambda//2)=2+4gt0` Hence f(x) has maixmum for no real value of `lambda` When `lambda =-1 f(x)=0` if x=1 so f(x) has a point of inflection at x=1 |
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