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Consider that, a ball is immersed in water at room temperature and then taken out having 18 grams of water on it, how much amount of energy is required to dry that water at room temperature?(a) 41.43 KJ/mol(b) 49.53 KJ/mol(c) 41.3 KJ/mol(d) 41.53 KJ/molThe question was asked by my college professor while I was bunking the class.I need to ask this question from Thermodynamics topic in chapter Thermodynamics of Chemistry – Class 11

Answer»

Correct choice is (d) 41.53 KJ/mol

Best EXPLANATION: HEAT required to eliminate water : n x ΔvapH^– = (1 mol) × (44.01 kJ mol^–1) = 44.01 kJ mol^-1. Δvapor = ΔvapH – ΔnRT = 44.01 kJ mol^-1 – 1×8.314 J/K-mol x 298 k x 10^-3 = 41.53 KJ/mol. So the amount of energy NEEDED is 41.53 KJ/mol.



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