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Consider the following nuclear reactions : `._(92)^(238)M rarr _(Y)^(X)N+2 . _(2)^(4)He, ._(Y)^(X)N rarr _(B)^(A)L+2beta^(+)` The number of neutrons in the element L isA. 142B. 144C. 140D. 146 |
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Answer» Correct Answer - B `._(92)^(238)M rarr _(Y)^(X)N+2._(2)^(4)He` Applying mass number balance & nuclear charge balance 92=y+4 `" "` y=88 238=x+8 ` " "` x=230 `._(Y)^(X)N rarr _(B) ^(A) L+2 beta^(+) (._(+1)e^(0))` Applying mass number balance & nuclear charge balance 230=A+0 `" "` A=230 88=B+2 ` " " ` B=86 No. of neutrons in element L is 230-86=144. |
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