InterviewSolution
Saved Bookmarks
| 1. |
Consider the reaction : `2H_(2)(g)+2NO(g)rarrN_(2)(g)+2H_(2)(g)` The rate law for this reaction is : Rate = `k[H_(2)][NO]^(2)` Under what conditions could these steps represent mechanism? `{:("Step 1:",2NO(g)hArrN_(2)O_(2)(g)),("Step 2:",N_(2)O_(2)+H_(2)rarrN_(2)O+H_(2)O),("Step 3:",N_(2)O+H_(2)rarrH_(2)O+N_(2)):}`A. These steps can never satisfy the rate lawB. Step 1 should be the slowest stepC. Step 2 should be the slowest stepD. Step 3 should be the slowest step |
| Answer» Correct Answer - C | |