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| 1. |
Consider the reaction: `N_(2(g))+3H_(2(g))rarr 2NH_(3(g))`. The equally relationship between `-(d[NH_(3)])/(dt)` and `-(d[H_(2)])/(dt)` is: |
| Answer» `-1/3(d[H_(2)])/(dt) = +1/2(d[NH_(3)])/(dt)` | |