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Consider the reaction: `N_(2(g))+3H_(2(g))rarr 2NH_(3(g))`. The equally relationship between `-(d[NH_(3)])/(dt)` and `-(d[H_(2)])/(dt)` is:A. `(d[NH_(3)])/(dt) = (-d[H_(2)])/(dt)`B. `(d[NH_(3)])/(dt) = -1/3(d[H_(2)])/(dt)`C. `(d[NH_(3)])/(dt) = -2/3 (d[H_(2)])/(dt)`D. `(d[NH_(3)])/(dt) = -3/2 (d[H_(2)])/(dt)` |
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Answer» Correct Answer - C c) is the correct relation. |
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