1.

Consider the shown arrangement. Assume all surfaces to be smooth. If N represents magnitudes of normal reaction between block and wedge, then acceleration of M along horizontal is equla to A. `(N sin theta)/(M)` along + veX-axisB. `(N cos theta)/(M)` along - veX-axisC. `(N sin theta)/(M)` along - veX-axisD. `(N sin theta)/(m+M)` along - veX-axis

Answer» Correct Answer - C
( c) Wedge move due to horizontal component of normal reaction.
Thus `" " a=(N_(H))/(M)=(N sin theta)/(M)" " `(along-ve X-axis)


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