InterviewSolution
Saved Bookmarks
| 1. |
Construct a quadrilateral ABCD with AB=3 cm, AB=3cm, AD=2.7 cm, DB=3.6 cm, angleB=110^(@) and BC=4.2 cm. Construct another quadrilateral A'BC'D' similar to quadrilateral ABCD so that diagonal BD'=4.8 cm. |
|
Answer» Solution :Steps of construction: 1. Draw a line segment BC=4.2 2. At B, construct angle YBC`=110^(@)`. 3. With centre B and RADIUS equalt to 3cm draw ab arc cutting BY at A. 4. With centre A and radius equals to 2.7 cm, draw an arc . 5. With centre B and radius equals to 3.6 cm, draw another arc cutting the previous arc at D. 6. JOIN AD, CD and BD. Then, ABCD is the required quadrilateral . 7. Produce BD to D' such that BD'=4.8 cm. 8. From D', draw a line parallel to DAwhich cuts BY at A' 9. From D', draw a line parallel to DC when cuts BC produced atD'. Then `squareA'BC'D'` is the required quadrilateral similar to `squareABCD`.
|
|