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Construct a quadrilateral ABCD with AB=3 cm, AB=3cm, AD=2.7 cm, DB=3.6 cm, angleB=110^(@) and BC=4.2 cm. Construct another quadrilateral A'BC'D' similar to quadrilateral ABCD so that diagonal BD'=4.8 cm.

Answer»

Solution :Steps of construction:
1. Draw a line segment BC=4.2
2. At B, construct angle YBC`=110^(@)`.
3. With centre B and RADIUS equalt to 3cm draw ab arc cutting BY at A.
4. With centre A and radius equals to 2.7 cm, draw an arc .
5. With centre B and radius equals to 3.6 cm, draw another arc cutting the previous arc at D.
6. JOIN AD, CD and BD. Then, ABCD is the required quadrilateral .
7. Produce BD to D' such that BD'=4.8 cm.
8. From D', draw a line parallel to DAwhich cuts BY at A'
9. From D', draw a line parallel to DC when cuts BC produced atD'. Then `squareA'BC'D'` is the required quadrilateral similar to `squareABCD`.


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