Convert 1 Newton Into Dyne Using Method Of Dimensions?

1.	Convert 1 Newton Into Dyne Using Method Of Dimensions?
Answer» Dimensions of Force = [M1L1T-2] Considering dimensional unit CONVERSION formula i.e. n1[M1aL1bT1c] = N2[M2aL2bT2c] ⇒ a = 1, b = 1 and c = -2 In SI system, M1 = 1kg, L1 = 1m and T1 = 1s In cgs system, M2 = 1g, L2 = 1cm and T2 = 1s PUTTING the values in the conversion formula, n2 = n1(1Kg/1g)1.(1m/1cm)1(1s/1s)-2= 1.(103/1g)(102cm) = 105dyne Dimensions of Force = [M1L1T-2] Considering dimensional unit conversion formula i.e. n1[M1aL1bT1c] = n2[M2aL2bT2c] ⇒ a = 1, b = 1 and c = -2 In SI system, M1 = 1kg, L1 = 1m and T1 = 1s In cgs system, M2 = 1g, L2 = 1cm and T2 = 1s Putting the values in the conversion formula, n2 = n1(1Kg/1g)1.(1m/1cm)1(1s/1s)-2= 1.(103/1g)(102cm) = 105dyne

Answer»

Dimensions of Force = [M1L1T-2]

Considering dimensional unit CONVERSION formula i.e. n1[M1aL1bT1c] = N2[M2aL2bT2c]

⇒ a = 1, b = 1 and c = -2

In SI system, M1 = 1kg, L1 = 1m and T1 = 1s

In cgs system, M2 = 1g, L2 = 1cm and T2 = 1s

PUTTING the values in the conversion formula,

n2 = n1(1Kg/1g)1.(1m/1cm)1(1s/1s)-2= 1.(103/1g)(102cm) = 105dyne

Dimensions of Force = [M1L1T-2]

Considering dimensional unit conversion formula i.e. n1[M1aL1bT1c] = n2[M2aL2bT2c]

⇒ a = 1, b = 1 and c = -2

In SI system, M1 = 1kg, L1 = 1m and T1 = 1s

In cgs system, M2 = 1g, L2 = 1cm and T2 = 1s

Putting the values in the conversion formula,

n2 = n1(1Kg/1g)1.(1m/1cm)1(1s/1s)-2= 1.(103/1g)(102cm) = 105dyne

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