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Hooke’s Law States That The Force, F, In A Spring Extended By A Length X Is Given By F = −kx. According To Newton’s Second Law F = Ma, Where M Is The Mass And A Is The Acceleration. Calculate The Dimension Of The Spring Constant K? |
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Answer»
⇒ k = – F/x F = ma, the DIMENSIONS of force is: [F] = ma = [M1L0T0].[M0L1T-2] = [M1L1T-2] Therefore, DIMENSION of spring CONSTANT (k) is: [k] = [F]/[x] = [M1L1T-2].[M0L-1T0] = [M1L0T-2] or [MT-2] ….. Given, F = -kx ⇒ k = – F/x F = ma, the dimensions of force is: [F] = ma = [M1L0T0].[M0L1T-2] = [M1L1T-2] Therefore, dimension of spring constant (k) is: [k] = [F]/[x] = [M1L1T-2].[M0L-1T0] = [M1L0T-2] or [MT-2] ….. |
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