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Convert `4(cos 300^(@) + i sin 300^(@))` into Cartesian form. |
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Answer» `4(cos 300^(@)+isin 300^(@))=4[cos(360^(@)-60^(@))+i sin(36^(@)-60^(@))]` `" "=4[cos(-60^(@))+i sin(-60^(@))]` `" "=4[cos60^(@)-i sin60^(@)]4((1)/(2)-i(sqrt(3))/(2))` `" "=(2-2i sqrt(3))` |
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