1.

`cos 42^(@)-sin48^(@)` का मान ज्ञात कीजिए.

Answer» यहाँ `cos 42^(@)-sin48^(@)=cos (90^(@)-48^(@))-sin48^(@)`
`=sin (48^(@))-sin48^(@)" "[because cos (90^(@)-theta)=sin theta]`
`=sin 48^(@)-sin 48^(@)=0`


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