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`cos 42^(@)-sin48^(@)` का मान ज्ञात कीजिए. |
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Answer» यहाँ `cos 42^(@)-sin48^(@)=cos (90^(@)-48^(@))-sin48^(@)` `=sin (48^(@))-sin48^(@)" "[because cos (90^(@)-theta)=sin theta]` `=sin 48^(@)-sin 48^(@)=0` |
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