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`cos((dy)/(dx))=a(a inR),y=1` यदि x = 0 |
Answer» दिया है, `cos((dy)/(dx))=aimplies(dy)/(dx)= cos^(-1)a` `implies dy=( cos^(-1)a)dx` `implies intdy=cos^(-1)a int dx` `implies y=cos^(-1)a(x)+C" ....(1)"` y = 1 तथा x = 0 तो `1 = cos^(-1)(a)xx0+CimpliesC=1` समीकरण (1) में C = 1 रखने पर, `y=x cos^(-1)a+1implies(y-1)/(x)=cos^(-1)a` `implies cos((y-1)/(x))=a` जोकि अभीष्ट विशिष्ट हल है। |
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