1.

`cos((dy)/(dx))=a(a inR),y=1` यदि x = 0

Answer» दिया है, `cos((dy)/(dx))=aimplies(dy)/(dx)= cos^(-1)a`
`implies dy=( cos^(-1)a)dx`
`implies intdy=cos^(-1)a int dx`
`implies y=cos^(-1)a(x)+C" ....(1)"`
y = 1 तथा x = 0 तो `1 = cos^(-1)(a)xx0+CimpliesC=1` समीकरण (1) में C = 1 रखने पर,
`y=x cos^(-1)a+1implies(y-1)/(x)=cos^(-1)a`
`implies cos((y-1)/(x))=a`
जोकि अभीष्ट विशिष्ट हल है।


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