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Cot theta. Tan(90-theta)-sec(90-theta) cosec theta +√3 tan 12.tan60.tan78=2 |
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Answer» let theta = A According to the QUESTION, COT A . TAN (90 - A) - SEC (90 - A) . cosecA + √3 . tan12 . TAN60 . tan78 =2 LHS : cot A . tan (90 - A) - sec (90 - A) . cosecA + √3 . tan12 . tan60 . tan78
Hence Proved ! |
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