1.

CucuitThis charge deposited on 4uf Capacitor the circuitis+12 V2 uf6 ufD 6X 10-6c3 24 x 10-6-c2) 12 x 10-6ca) 25 x 10-6c​

Answer»

ANSWER:

Explanation:

As the capacitors 4μF and 2μF are connected in parallel and are in SERIES with 6μF capacitor, their EQUIVALENT capacitance is

(2+4)×62+4+6=3μF

Charge in the circuit,

Q=3μF×12V=36μC

image

Since, the capacitors 4μF and 2μF are connected in parallel, THEREFORE potential difference across them is same.

⇒Q1Q2=C1C2=42

or Q1=2Q2

Also, Q=Q1+Q2

∴36μC=2Q2+Q2

or Q2=36μC3=12μC

Q1=Q−Q2=36μC−12μC

=24μC=24×10−6C


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