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Cyclopropane rearranges to form propene `to CH_(3) - CH = CH_(2)` This follows first order kinetics. The rate constant is `2.714 xx 10^(-3) sec^(-1)`. The unitial concentration of cyclopropane is 0.29 M. What will be the concentraion of cyclopropane after 100 sec?A. 0.035 MB. 0.22 MC. 0.145 MD. 0.0018 M |
Answer» Correct Answer - B `k = (2.303)/(t) "log" (a)/((a - x))` (a - x) is the concentration left after 100 sec. `2.7 xx 10^(-3) = (2.303)/(100) "log" (0.29)/((a - x))` `implies (0.27)/(2.303) = "log" (0.29)/((a -x)) implies 0.117 = "log" (0.29)/((a - x))` `implies (a - x) = 0.22 M` |
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