InterviewSolution
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InterviewSolution
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`(d^2x)/(dy^2)`equals:(1) `((d^2y)/(dx^2))^(-1)`(2) `-((d^2y)/(dx^2))^(-1)((dy)/(dx))^(-3)`(3) `((d^2y)/(dx^2))^(-1)((dy)/(dx))^(-2)`(4) `-((d^2y)/(dx^2))^(-1)((dy)/(dx))^(-3)`A. `((d^(2)y)/(dx^(2)))^(-1)`B. `-((d^(2)y)/(dx^(2)))^(-1)((dy)/(dx))^(-3)`C. `((d^(2)y)/(dx^(2)))((dy)/(dx))^(-2)`D. `-((d^(2)y)/(dx^(2)))((dy)/(dx))^(-3)` |
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Answer» Correct Answer - D Since, `(dx)/(dy) = 1/(dy//dx) = ((dy)/(dx))^(-1) ` ` rArr" " d/(dy) ((dx)/(dy)) = d/(dx) ((dy)/(dx))^(-1) (dx)/(dy) ` ` rArr" " (d^(2)x)/(dy^(2)) =- ((d^(2)y)/(dx^(2)))((dy)/(dx))^(-2)((dx)/(dy)) =- ((d^(2)y)/(dx^(2))((dy)/(dx))^(-3) ` |
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