1.

d. 4i+ 2j3. A stone is thrown upwards at a speed of 20m/s, what is it's speed (in m/s) and direction after 3secondsa. 10, upwardsb. 20, downwardsC. 10, downwardsd. 0

Answer»

Velocity at maximum height (v) = 0Acceleration = -g(-ve sign because it’s in the direction opposite to motion of stone)

v² - u² = 2aS

S = v² - u² / (2a)= [0 - (20 m/s)²] / [2 × (-9.8 m/s²)]= 20.40 m

It will reach a height of 20.40 m before it begins to fall.

answer is b part.



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