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                                    d. An electric iron of 1100 W isoperated for 2 hrs daily. What willbe the electrical consumptionexpenses for that in the month ofApril? (The electric companycharges Rs 5 per unit of energy(Ans : Rs 330) | 
                            
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Answer»  Energy = 1100W = 1.1Kw Energy=power*time=1.1(kw)*2(hr)=2.2kwh Energy used in a day=2.2 unit Energy used in 30 days= 2.2×30unit = 66unit Total cost=66×5=330 rs  | 
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