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Answer»

Maximum height = (V sin0)² / 2g= (28 sin30)²/ 2 x 9.8

= 14 x 14 / 2 x 9.8= 10m

time taken to return to the same level=2 v sin0/ g= 2 x 28 x sin30/ 9.8= 2 x 28 x 1/ 2 x 9.8= 2.9 sec

distance from thrower to where the ball returns= v² sin 2Ф/ g= 28 x 28 x sin60/ 9.8= 69.3 m



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